mysql5.7支持JSONField
当我想设置一个简单的密码时,提示`Your password does not satisfy the current policy requirements`
有没有办法输入一个简单的密码如123456
我们只需要登录mysql执行以下命令即可
mysql> set global validate_password_policy=0;
Query OK, 0 rows affected (0.05 sec)
mysql>
mysql>
mysql> set global validate_password_mixed_case_count=0;
Query OK, 0 rows affected (0.00 sec)
mysql> set global validate_password_number_count=3;
Query OK, 0 rows affected (0.00 sec)
mysql> set global validate_password_special_char_count=0;
Query OK, 0 rows affected (0.00 sec)
mysql> set global validate_password_length=3;
Query OK, 0 rows affected (0.00 sec)
mysql> SHOW VARIABLES LIKE 'validate_password%';
+--------------------------------------+-------+
| Variable_name | Value |
+--------------------------------------+-------+
| validate_password_dictionary_file | |
| validate_password_length | 3 |
| validate_password_mixed_case_count | 0 |
| validate_password_number_count | 3 |
| validate_password_policy | LOW |
| validate_password_special_char_count | 0 |
+--------------------------------------+-------+
6 rows in set (0.00 sec)
```
mysql> SET PASSWORD FOR 'root'@'localhost' = PASSWORD('123');
Query OK, 0 rows affected, 1 warning (0.00 sec)
```
以下是详细的说明
```
validate_password_dictionary_file
插件用于验证密码强度的字典文件路径。
validate_password_length
密码最小长度,参数默认为8,它有最小值的限制,最小值为:validate_password_number_count + validate_password_special_char_count + (2 * validate_password_mixed_case_count)
validate_password_mixed_case_count
密码至少要包含的小写字母个数和大写字母个数。
validate_password_number_count
密码至少要包含的数字个数。
validate_password_policy
密码强度检查等级,0/LOW、1/MEDIUM、2/STRONG。有以下取值:
Policy Tests Performed
0 or LOW Length
1 or MEDIUM Length; numeric, lowercase/uppercase, and special characters
2 or STRONG Length; numeric, lowercase/uppercase, and special characters; dictionary file
默认是1,即MEDIUM,所以刚开始设置的密码必须符合长度,且必须含有数字,小写或大写字母,特殊字符。
validate_password_special_char_count
密码至少要包含的特殊字符数。
```