1.取时间最新的记录 不分组有重复(多条CreateTime一样的都是最新记录)
select *
from test t
where
pid
in
(
select PId from Test t
where
time=(select max(time) from Test t1 where t1.PId=t.PId)
group by Pid
)
and
time=(select max(time) from Test t1 where t1.PId=t.PId)
2.分组后取时间最新的记录
SELECT max(Id)/*注意Id必须使用聚合函数Max*/ , Pid, MAX(Time) as MaxTime
FROM Test
GROUP BY pid
3.如果Id是uuid类型无法使用max(id)的解决办法(使用开窗函数)
select *
from
(
select row_number() over(partition by [Pid] order by [Time] desc /*降序是为了where KeyId=1 (1是固定值第一条),如果升序由于不知道每组多少条where中KeyId就无法过滤了*/ ) as KeyId,* from Test
) d
where KeyId=1
原文链接：https://blog.csdn.net/Wis57/article/details/129201601
